№6
Вопрос
номер 6
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Переключите год учебника.
Вопрос
Номер 6.
Перечертите в тетрадь и заполните таблицу
$$
\begin{array}{|c|l|l|l|l|l|l|l|l|}
\hline x & -13 & -5 & -0,2 & 0 & \frac{\mathbf{1}}{\mathbf{1 7}} & 1 & \mathbf{5} \frac{\mathbf{2}}{\mathbf{3}} & 7 \\
\hline \frac{\boldsymbol{x}+\mathbf{5}}{\boldsymbol{x}-\mathbf{3}} & & & & & & & & \\
\hline
\end{array}
$$
\begin{array}{|c|l|l|l|l|l|l|l|l|}
\hline x & -13 & -5 & -0,2 & 0 & \frac{\mathbf{1}}{\mathbf{1 7}} & 1 & \mathbf{5} \frac{\mathbf{2}}{\mathbf{3}} & 7 \\
\hline \frac{\boldsymbol{x}+\mathbf{5}}{\boldsymbol{x}-\mathbf{3}} & & & & & & & & \\
\hline
\end{array}
$$
Если x = −13, то x + 5/x − 3 = −13 + 5/−13 − 3 = −8/−16 = 1/2 = 0,5 Если x = −5, то x + 5/x − 3 = −5 + 5/−5 − 3 = 0/−8 = 0 Если x = −0,2, то x + 5/x − 3 = −0,2 + 5/−0,2 − 3 = 4,8/−3,2 = 4,8 ⋅ 10/−3,2 ⋅ 10 = 48/−32 = 48 : 16/−32 : 16 = − 3/2 = −1,5 Если x = 0, то x + 5/x − 3 = 0 + 5/0 − 3 = 5/−3 = −5/3 = −1 2/3 Если x = 1/17 , то x + 5/x − 3 = $$
\frac{\frac{1}{17}+5}{\frac{1}{17}-3}=\frac{5 \frac{1}{17}}{-2 \frac{1}{17}}=\frac{\frac{5 \cdot 17+1}{17}}{\frac{-(2 \cdot 17+16)}{17}}=\frac{\frac{86}{17}}{\frac{-50}{17}}
$$ = 86/17 : −50/17 = 86/17 ⋅ (− 17/50 ) = − 86/50 = −1,72 Если x = 1, то x + 5/x − 3 = 1 + 5/1 − 3 = 6/−2 = −3/1 = −3 Если x = 5 2/3 , то x + 5/x − 3 = $$
\frac{5 \frac{2}{3}+5}{5 \frac{2}{3}-3}=\frac{10 \frac{2}{3}}{2 \frac{2}{3}}=
$$ = 10 ⋅ 3 + 2/2 ⋅ 3 + 2 = 30 + 2/6 + 2 = 32/8 = 4 Если x = 7, то x + 5/x − 3 = 7 + 5/7 − 3 = 12/4 = 3
Если x = −13, то
x + 5/x − 3 = −13 + 5/−13 − 3 = −8/−16 = 1/2 = 0,5
x + 5/x − 3
−13 + 5/−13 − 3
−8/−16
1/2
Если x = −5, то
x + 5/x − 3 = −5 + 5/−5 − 3 = 0/−8 = 0
x + 5/x − 3
−5 + 5/−5 − 3
0/−8
Если x = −0,2, то
x + 5/x − 3 = −0,2 + 5/−0,2 − 3 = 4,8/−3,2 = 4,8 ⋅ 10/−3,2 ⋅ 10 = 48/−32 = 48 : 16/−32 : 16 = − 3/2 = −1,5
x + 5/x − 3
−0,2 + 5/−0,2 − 3
4,8/−3,2
4,8 ⋅ 10/−3,2 ⋅ 10
48/−32
48 : 16/−32 : 16
3/2
Если x = 0, то
x + 5/x − 3 = 0 + 5/0 − 3 = 5/−3 = −5/3 = −1 2/3
x + 5/x − 3
0 + 5/0 − 3
5/−3
−5/3
2/3
Если x = 1/17 , то
1/17
x + 5/x − 3 = $$
\frac{\frac{1}{17}+5}{\frac{1}{17}-3}=\frac{5 \frac{1}{17}}{-2 \frac{1}{17}}=\frac{\frac{5 \cdot 17+1}{17}}{\frac{-(2 \cdot 17+16)}{17}}=\frac{\frac{86}{17}}{\frac{-50}{17}}
$$ = 86/17 : −50/17 = 86/17 ⋅ (− 17/50 ) = − 86/50 = −1,72
x + 5/x − 3
86/17
−50/17
86/17
17/50
86/50
Если x = 1, то
x + 5/x − 3 = 1 + 5/1 − 3 = 6/−2 = −3/1 = −3
x + 5/x − 3
1 + 5/1 − 3
6/−2
−3/1
Если x = 5 2/3 , то
2/3
x + 5/x − 3 = $$
\frac{5 \frac{2}{3}+5}{5 \frac{2}{3}-3}=\frac{10 \frac{2}{3}}{2 \frac{2}{3}}=
$$ = 10 ⋅ 3 + 2/2 ⋅ 3 + 2 = 30 + 2/6 + 2 = 32/8 = 4
x + 5/x − 3
10 ⋅ 3 + 2/2 ⋅ 3 + 2
30 + 2/6 + 2
32/8
Если x = 7, то
x + 5/x − 3 = 7 + 5/7 − 3 = 12/4 = 3
x + 5/x − 3
7 + 5/7 − 3
12/4
